A solid disk with a radius of $5 m$ and mass of $4 kg$ is rotating on a frictionless surface. If $15 W$ of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at $12 Hz$ ?

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Answer 1 · 2018-04-04T14:50:53

The torque is $=0.16Nm$

Apply the equation

$"Power (W)" ="torque(Nm)"xx"angular velocity" (rad s^-1)$

The power is $P=15W$

The frequency is $f=12Hz$

The angular velocity is

$omega=2pif=2xxpixx12=(24pi)rads^-1$

Therefore,

The torque is

$tau=P/omega=12/(24pi)=0.16Nm$

A solid disk with a radius of 5 m5 m and mass of 4 kg4 kg is rotating on a frictionless surface. If 15 W15 W of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at 12 Hz12 Hz?