A solid disk with a radius of 3 m and mass of 9 kg is rotating on a frictionless surface. If 120 W of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at 8 Hz?

1 Answer
Feb 9, 2017

tau=(120" W")/(16pi)~~2.39N*m

Explanation:

We are told we have a rotating spinning coin.

![http://www.mariowiki.com/coin](useruploads.socratic.org)

Step 1. Gather the information that you know and need

  • Mass of disk: "mass"=m=9" kg"
  • Radius of disk: "radius"=r=3" m"
  • Power applied to increase rotation: P=120" W"
  • Frequency: f=8" Hz"
  • Torque required: ??

Step 2. Determine the formula using the above givens

  • P is the power applied, P=tau omega
  • Therefore, the formula for torque is tau=P"/"omega
  • Angular speed, omega=f*2pi=8*2pi=16pi

Step 3. Plug your answer into the formula for torque

tau=(120" W")/(16pi)~~2.39N*m