A solid disk with a radius of $3 m$ and mass of $4 kg$ is rotating on a frictionless surface. If $750 W$ of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at $4 Hz$ ?

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Answer 1 · 2017-04-21T09:23:32

The torque is $=29.84Nm$

Mass of disc $=4kg$

Radius of disc $=3m$

The power is related to the torque by the equation

$P=tau *omega$

$P=750W$

Frequency of rotation is $f=4Hz$

$omega=f*2pi$

angular velocity, $omega=4*2pi rads^-1$

torque, $tau=P/omega$

$=750/(8pi)=29.84Nm$

A solid disk with a radius of 3 m3 m and mass of 4 kg4 kg is rotating on a frictionless surface. If 750 W750 W of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at 4 Hz4 Hz?