A solid disk with a radius of $3 m$ and mass of $12 kg$ is rotating on a frictionless surface. If $480 W$ of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at $4 Hz$ ?

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Answer 1 · 2017-03-17T11:22:59

The torque is $=19.1Nm$

mass of disc $=12kg$

radius of disc $=3m$

The power is related to the torque by the equation

$P=tau *omega$

$P=480W$

angular velocity, $omega=4*2pi rads^-1$

torque, $tau=P/omega$

$=480/(8pi)=60/pi=19.1Nm$

A solid disk with a radius of 3 m3 m and mass of 12 kg12 kg is rotating on a frictionless surface. If 480 W480 W of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at 4 Hz4 Hz?