A solid disk with a radius of $2 m$ $2 m$ and mass of $4 k g$ $4 kg$ is rotating on a frictionless surface. If $480 W$ $480 W$ of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at $9 H z$ $9 Hz$ ?

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Answer 1 · 2017-02-09T19:32:16

$τ = \frac{480 W}{18 π} \approx 8.49 N \cdot m$ $tau=(480W)/(18pi)~~8.49N*m$

We are told we have a rotating spinning coin.

![http://www.mariowiki.com/coin]( useruploads.socratic.org )

Step 1. Gather the information that you know and need

Step 2. Determine the formula using the above givens

Step 3. Plug your knows into the formula for torque

$τ = \frac{480 W}{18 π} \approx 8.49 N \cdot m$ $tau=(480W)/(18pi)~~8.49N*m$

A solid disk with a radius of 2m2 m and mass of 4kg4 kg is rotating on a frictionless surface. If 480W480 W of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at 9Hz9 Hz?