A solid disk with a radius of $2 m$ and mass of $2 kg$ is rotating on a frictionless surface. If $15 W$ of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at $1 Hz$ ?

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Answer 1 · 2017-04-05T08:22:18

The torque is $=2.39Nm$

mass of disc $=2kg$

radius of disc $=2m$

The power is related to the torque by the equation

$P=tau *omega$

$P=15W$

Frequency of rotation is $f=1Hz$

$omega=f*2pi$

angular velocity, $omega=1*2pi rads^-1$

torque, $tau=P/omega$

$=15/(2pi)=2.39Nm$

A solid disk with a radius of 2 m2 m and mass of 2 kg2 kg is rotating on a frictionless surface. If 15 W15 W of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at 1 Hz1 Hz?