A solid disk, spinning counter-clockwise, has a mass of #5 kg# and a radius of #6 m#. If a point on the edge of the disk is moving at #6 m/s# in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

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Answer 1 · 2017-11-30T14:33:40

The angular momentum is #=2.5kgm^2s^-1#. The angular velocity is #=1rads^-1#

The angular velocity is

#omega=(Deltatheta)/(Deltat)#

#v=r*((Deltatheta)/(Deltat))=r omega#

#omega=v/r#

where,

#v=6ms^(-1)#

#r=6m#

So,

The angular velocity is

#omega=(6)/(6)=1rads^-1#

The angular momentum is #L=Iomega#

For a solid disc, #I=(mr^2)/2#

The mass is #m= 5kg#

So, #I=5*(1)^2/2=2.5kgm^2#

The angular momentum is

#L=2.5*1=2.5kgm^2s^-1#