A serving of Cheez-Its releases 130 kcal (1 kcal = 4.18 kJ) when digested by your body. If this same amount of energy were transferred to 2.5 kg of water at 27°C ,what would the final temperature be?

1 Answer
Dec 25, 2015

78,925^@C

Explanation:

Energy transferred (W) is given by

W=mcDeltaT,

where m is the mass, c is the specific heat capacity, and Delta T is the change in temperature.

So in this case,

DeltaT=W/(mc)=(4180Jxx130)/((2,5kg)*(4186J//kg.K))=51,925^@C.

Therefore the final temperature of the water will be

T_f=27+51,925=78,925^@C.