A serving of Cheez-Its releases 130 kcal (1 kcal = 4.18 kJ) when digested by your body. If this same amount of energy were transferred to 2.5 kg of water at 27°C ,what would the final temperature be?

Question

14357 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-12-25T15:51:45

#78,925^@C#

Energy transferred (W) is given by

#W=mcDeltaT#,

where #m# is the mass, #c# is the specific heat capacity, and #Delta T# is the change in temperature.

So in this case,

#DeltaT=W/(mc)=(4180Jxx130)/((2,5kg)*(4186J//kg.K))=51,925^@C#.

Therefore the final temperature of the water will be

#T_f=27+51,925=78,925^@C#.