A saturated solution of $PbBr_2$ is prepared by dissolving the solid salt in water. The concentration of $Pb_2^+$ in solution is found to be 0.0115 M. What is the Ksp for $PbBr_2$ ?

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Answer 1 · 2017-07-14T19:01:37

$K_(sp)=6.1xx10^-6$

We interrogate the solubility equilibrium.........

$PbBr_2(s) rightleftharpoonsPb^(2+) + 2Br^(-)$

Now $K_(sp)=[Pb^(2+)][Br^-]$ .........And if we say that the solubility of $PbBr_2-=S$ , then by stoichiometry........

$K_(sp)=[S][2S]^2=4S^3$ (because $S=[Pb^(2+)]$ , and $[Br^-]=2S$

$=4xx(0.0115)^3=6.1xx10^-6$ .........

Can you define what is meant by a $"saturated solution......?"$

A saturated solution of PbBr_2PbBr_2 is prepared by dissolving the solid salt in water. The concentration of Pb_2^+Pb_2^+ in solution is found to be 0.0115 M. What is the Ksp for PbBr_2PbBr_2?