A sample of compressed methane has a volume of 648 mL at a pressure of 503 kPa. To what pressure would the methane have to be compressed in order to have a volume of 216 mL?

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Answer 1 · 2017-03-14T08:59:17

The pressure is #=1509kPa#

#P_1V_1=P_2V_2#

#P_1=503kPa#

#V_1=648mL#

#V_2=216mL#

#P_2=V_1/V_2*P_1#

#=648/216*503=1509kPa#

Answer 2 · 2017-03-14T09:01:02

Well, Boyle's law holds that #P_1V_1=P_2V_2#............

So we solve for #P_2=(P_1V_1)/V_2=(503*kPaxx648*mL)/(216*mL)=??*kPa#.

Clearly, the pressure increases, here almost threefold.