A sample of $C_{3} H_{8}$ $C_3H_8$ has $6.72 \times 10^{24}$ $6.72 times 10^24$ $H$ $H$ atoms. How many carbon atoms does the sample contain?

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A sample of $C_{3} H_{8}$ $C_3H_8$ has $6.72 \times 10^{24}$ $6.72 times 10^24$ $H$ $H$ atoms. How many carbon atoms does the sample contain?

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Answer 1 · 2017-07-05T04:52:08

Would this not simply be $\frac{3}{8} \times 6.72 \times 10^{24}$ $3/8xx6.72xx10^24$ $carbon atoms$ $"carbon atoms"$ ?

Explanation:

If we have $6.72 \times 10^{24}$ $6.72xx10^24$ hydrogen atoms in the propane sample, surely given the formula of propane, i.e. $C_{3} H_{8}$ $C_3H_8$ , there would be $\frac{3}{8} \times 6.72 \times 10^{24}$ $3/8xx6.72xx10^24$ individual carbon atoms......

The numbers here are pretty irrelevant (meaning that I could choose any number), save that we also know that $Avogadro's Number$ $"Avogadro's Number"$ of $propane molecules$ $"propane molecules"$ , $6.022 \times 10^{23}$ $6.022xx10^23$ individual molecules of propane, has a mass of $44.1 \cdot g$ $44.1*g$ . Can you tell us the mass of the given quantity of propane in the question?

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A sample of $C_{3} H_{8}$ $C_3H_8$ has $6.72 \times 10^{24}$ $6.72 times 10^24$ $H$ $H$ atoms. How many carbon atoms does the sample contain?

1 Answer

Explanation:

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A sample of C3H8C_3H_8 has 6.72×10246.72 times 10^24 HH atoms. How many carbon atoms does the sample contain?

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Explanation:

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A sample of $C_{3} H_{8}$ $C_3H_8$ has $6.72 \times 10^{24}$ $6.72 times 10^24$ $H$ $H$ atoms. How many carbon atoms does the sample contain?