A rope of length L is pulled by a constant force f. what is the tension in the Rope at a distance x from the end where the force is applied?

1 Answer
Mar 22, 2018

See an explanation below

Explanation:

This is also an open question.

The simplest answer (if the rope is weightless) is that according to Newton's Third Law, the

Tension is #=fN#

Suppose the diameter of the rope is #=(d)m#

The cross sectional area of the rope is #A=(pid^2/4)m^2#

Suppose the density of the material of the rope is #=(rho)kgm^-3#

Then the mass of the rope of length #xm# is

#m=(pid^2/4*x*rho) kg#

The weight of the rope is

#w=(pid^2/4*x*rho*g) N#

Where the acceleration due to gravity is #g=9.8ms^-2#

Therefore,

The tension in the rope is

#T=(f+(pid^2/4*x*rho*g)) N#