A roller coaster cart with mass m= 150 kg is at the top of a ride travelling at $v_0 = 10$ m/s on frictionless tracks. The cart then descends on the almost vertical drop of the ride. The height is 110 m high. What is the cart's speed at base of the ride?

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A roller coaster cart with mass m= 150 kg is at the top of a ride travelling at $v_0 = 10$ m/s on frictionless tracks. The cart then descends on the almost vertical drop of the ride. The height is 110 m high. What is the cart's speed at base of the ride?

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Answer 1 · 2015-11-08T17:38:03

$47.5"m/s"$

Explanation:

I will apply the conservation of energy. The sum of the kinetic and potential energy at the top of the ride will be converted into kinetic energy at the bottom:

$1/2mv_0^2+mgh=1/2mv^2$

$:.1/2xx150xx10^2+(150xx9.8xx110)=1/2xx150xxv^2$

$:.7500+161700=75v^2$

$:.v=sqrt(2256)$

$v=47.5"m/s"$

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A roller coaster cart with mass m= 150 kg is at the top of a ride travelling at $v_0 = 10$ m/s on frictionless tracks. The cart then descends on the almost vertical drop of the ride. The height is 110 m high. What is the cart's speed at base of the ride?

1 Answer

Explanation:

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Impact of this question

Science

Math

Humanities

... and beyond

A roller coaster cart with mass m= 150 kg is at the top of a ride travelling at v_0 = 10v_0 = 10 m/s on frictionless tracks. The cart then descends on the almost vertical drop of the ride. The height is 110 m high. What is the cart's speed at base of the ride?

1 Answer

Explanation:

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Impact of this question

A roller coaster cart with mass m= 150 kg is at the top of a ride travelling at $v_0 = 10$ m/s on frictionless tracks. The cart then descends on the almost vertical drop of the ride. The height is 110 m high. What is the cart's speed at base of the ride?