A right angle triangle has sides of x+6, x+5 and x-2, how do you write the expression for the perimeter?

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A right angle triangle has sides of x+6, x+5 and x-2, how do you write the expression for the perimeter?

1 Answer

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Answer 1 · 2016-04-23T14:26:24

, #p =3x+9=30#

Explanation:

Being rt angled

#(x+6)^2=(x+5)^2+(x-2)^2#
#=>cancel(x^2)+12x+36=cancel(x^2)+10x+25+x^2-4x+4#
#=>x^2-6x-7=0#
#=>x^2-7x+x-7=0#
#=>(x-7)(x+1)#
#:. x=7#
perimeter, #p =x+6+x+5+x-2#
, #p =3xx7+9=30#

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A right angle triangle has sides of x+6, x+5 and x-2, how do you write the expression for the perimeter?

1 Answer

Explanation:

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