A projectile is shot from the ground at a velocity of $5 m/s$ at an angle of $(5pi)/12$ . How long will it take for the projectile to land?

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Answer 1 · 2017-01-30T08:18:57

The answer is $0.99 s$

Resolving in the vertical direction $uarr^+$

$u=5sin(5/12pi) ms^-1$

$a=-g ms^-2$

$s=0m$

We use the equation

$s=ut+1/2at^2$

$0=5sin(5/12pi)*t-g/2t^2$

$t(5sin(5/12pi)-g/2t)=0$

Therefore,

$t=0$ , this is when the projectile is shot

and

$5sin(5/12pi)-g/2t=0$

$t=10/gsin(5/12pi)$

$t=10/9.8sin(5/12pi)=0.99s$

A projectile is shot from the ground at a velocity of 5 m/s5 m/s at an angle of (5pi)/12(5pi)/12. How long will it take for the projectile to land?