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A projectile is shot from the ground at a velocity of #3 m/s# at an angle of #pi/4#. How long will it take for the projectile to land?

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MattyMatty · Stefan V.

Dec 1, 2017

#"0.432 s"#

Explanation:

#v = "3 m/s" = sqrt((v_h)² + (v_v)²)#

#"Angle" = 45^@ => v_"horiz" = v_"vertik" = 3/sqrt(2)#

Since

#v = g t => t = v/g = 3/(sqrt(2) * g)#

#t =# time to fall, here we have the double of that: rise & fall

#=> T = 6/(sqrt(2) * g) = "0.432 s"#

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