A projectile is shot from the ground at a velocity of #23 m/s# at an angle of #pi/3#. How long will it take for the projectile to land?

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Answer 1 · 2016-10-22T12:31:24

The time is #3.98#s

We use the formula

#y = y_0 + v_0yt + ½at^2 #

#v_0=23sin(pi/3) #

#y=y_0=0#

#a=-g#
We need to find t

#0=0+23tsin(pi/3)-( g t^2)/2#

So #t=0# or #t=(2*23sin(pi/3))/g#

Take #g=10#

Then #t=(2*23sin(pi/3))/10=(23sin(pi/3))/5=3.98 s#