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A projectile is shot from the ground at a velocity of #2 m/s# and at an angle of #(2pi)/3#. How long will it take for the projectile to land?

1 Answer

Oct 12, 2017

#(2sqrt(3))/10# seconds

Explanation:

#T = (2u sin θ) / g#

#T = (2 × 2 ms^-1 sin ((2 π)/3)) / (10 ms^-2)#

#T = (4 × sqrt(3)/2) / (10)# s

#T = (2sqrt(3))/10# #text(seconds)#

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