A projectile is shot from the ground at a velocity of #18 m/s# at an angle of #pi/6#. How long will it take for the projectile to land?

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A projectile is shot from the ground at a velocity of #18 m/s# at an angle of #pi/6#. How long will it take for the projectile to land?

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Answer 1 · 2016-01-05T19:46:49

#T=1.8367s#

Explanation:

Data:-
Velocity#=v_0=18m/s#
Angle#=theta=pi/6#
Time of flight#=T=??#
Acceleration due to gravity#=g=9.8m/s^2#
Sol:-
We know that:
#T=(2v_0sintheta)/g#
#implies T=(2*18Sin(pi/6))/9.8=(36*0.5)/9.8=18/9.8=1.8367s#
#implies T=1.8367s#

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A projectile is shot from the ground at a velocity of #18 m/s# at an angle of #pi/6#. How long will it take for the projectile to land?

1 Answer

Explanation:

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