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A projectile is shot from the ground at a velocity of #18 m/s# and at an angle of #(2pi)/3#. How long will it take for the projectile to land?

1 Answer

Feb 11, 2016

#t~=3,18 s#

Explanation:

#t=(2*v_i*sin alpha)/(g) " elapsed time"#
#alpha=(2pi)/3*180/pi=120^o#
#sin 120^o=sin 60^o~=0,866#
#t=(2*18*0,866)/(9,81)#
#t~=3,18 s#

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