A projectile is shot from the ground at a velocity of #15 m/s# at an angle of #(5pi)/12#. How long will it take for the projectile to land?

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Answer 1 · 2017-03-31T06:45:26

The time is #=2.96s#

Resolving in the vertical direction #uarr^+#

initial velocity is #u=vsintheta=15*sin(5/12pi)#

distance travelled #=0#

We apply the equation of motion

#s=ut+1/2at^2#

#0=15sin(5/12pi)*t-1/2*g*t^2#

Therefore,

#t=0# which is the initial condition and

#t=2*15/g*sin(5/12pi)#

#=2.96s#