A projectile is shot from the ground at a velocity of #1 m/s# at an angle of #pi/4#. How long will it take for the projectile to land?

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Answer 1 · 2017-01-17T14:14:32

The time is #=0.144s#

Computing in the vertical direction

#uarr^+#

#u=1*sin(pi/4)ms^-1#

#y=0#

#a=-9.8ms^2#

We use the equation

#y=ut+1/2at^2#

#0=sin(pi/4)t+1/2*-9.8*t^2#

#t(sin(pi/4)-4.9t)=0#

Therefore,

#t=0# which is the initial time

#t=1/4.9sin(pi/4)=0.144s#