A projectile is shot at an angle of #pi/4 # and a velocity of # 1 m/s#. How far away will the projectile land?

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Answer 1 · 2016-10-04T07:23:36

#x_"max"=0.1" m"#

#x_max=(v_i^2*sin(2 alpha))/g#

#v_i="the initial velocity of object"#

#alpha:" angle"#

#g=9.81 (N)/(kg)#

#"given : "#

#v_i=1 " "m/s#

#alpha= pi/4" ; " sin (2*pi/4)=sin (pi/2)=1#

#x_"max"=(1^2*1)/(9.81)=1/(9.81)#

#x_"max"=0.1" m"#