A person invested $50,000 into two accounts that pay 4 and 6% simple interest annually, respectively. How do you find the amount invested into the two accounts if the total interest earned after one year is $2400?

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Answer 1 · 2016-12-17T11:39:43

The person invested #$30000# at #4%# SI and #$20000# at #6%# SI

Let the person invested #$x# at #4%# SI.

Then the person invested #$(50000-x)# at #6%# SI.

The total interest earned after one year is # x*0.04+(50000-x)*0.06# which is equal to #$2400#

So #0.04x-0.06x+3000=2400 or -0.02x = -600 or x=600/0.02=$30000 :. 50000-x=50000-30000=$20000#

Therefore, the person invested #$30000# at #4%# SI. and invested #$20000# at #6%# SI.[Ans]