A patient with respiratory alkalosis has a blood plasma pH of 7.58. What is the [H_3O^+] of the blood plasma?

1 Answer
Nov 29, 2016

pH=-log_10[H_3O^+]. Here [H_3O^+] = 10^(-7.58)*mol*L^-1

Explanation:

Here [H_3O^+] = 10^(-7.58)*mol*L^-1=2.6xx10^-8*mol*L^-1.

[HO^-], so I presume, is elevated with this condition. What is [HO^-] here? What do you think it should be?