A particle P moves in a straight line. Velocity v ms^-1 at time t s is given by $v=5t(t-2)$ for $0<t<4$ $v=k$ for $4<t<14$ $V=68-2t$ for $14<t<20$ Find the set of values of t for which acceleration is positive?

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Answer 1 · 2018-05-16T06:01:01

The acceleration is positive when $t in (1,14)$

The acceleration is the derivative of the velocity

${(v(t)=5t^2-10t),(v(t)=k),(v(t)=68-2t):}$

The acceleration is

${(a(t)=10t-10),(a(t)=1),(a(t)=-2):}$

$a(t)>0$ when $t in (1,14)$

A particle P moves in a straight line. Velocity v ms^-1 at time t s is given by v=5t(t-2)v=5t(t-2) for 0<t<40<t<4 v=kv=k for 4<t<144<t<14 V=68-2tV=68-2t for 14<t<2014<t<20 Find the set of values of t for which acceleration is positive?