A particle of mass 10kg is placed in potential field given by V = (50x^2 + 100) erg/g. What will be frequency of oscillation of particle ?

1 Answer
Jane
Jan 28, 2018

For a conservative force acting, relation between potential energy and force is given as F= -(dU)/(dx) (here, given,V= potential ,so V*m=U=potential energy=10000(50x^2+100),see the unit)

So, differentiating the given equation,we get,

F= -100*10000x or, F/m =-100*10000/10000x = -100 x

Now, in case of a particle in S.H.M force equation is given as, F/m= - omega^2x

So,comparing the obtained force equation,we get, omega =sqrt(100) i.e 10 (rad)/s

This is the angular frequency.

So, nu = omega/(2 pi) = 1.6 s^-1

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