A NASCAR of mass 1400kg has broken down on pit lane. The coefficient of static friction between the tires and the road is 0.55. If the crew pushes with a force of 8046 N, what will the magnitude of the car's acceleration be?

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Answer 1 · 2015-10-09T14:40:52

$0,357m//s^2$

The static frictional force when motion just begins is given by
$f_s=mu_sN$
$=0,55xx1400xx9,8=7546N$

Hence the magnitude of the resultant force will be
$8046-7546=500N$

Therefore by Newton's 2nd Law of motion, the magnitude of the acceleration will be

$a=(sumF)/m=(500N)/(1400kg)=0,357m//s^2$