A NASCAR of mass 1400kg has broken down on pit lane. The coefficient of static friction between the tires and the road is 0.55. How hard would the crew have to push to get the car moving?

1 Answer
Trevor Ryan.
Oct 9, 2015

>=7546N≥7546N

Explanation:

The static frictional force when motion just begins is given by

f_s=mu_sNfs=μsN
=0,55xx1400xx9,8=7546N=0,55×1400×9,8=7546N

The applied force must hence be at least bigger than this in order to initiate motion.

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