A model train with a mass of #8 kg# is moving along a track at #15 (cm)/s#. If the curvature of the track changes from a radius of #45 cm# to #225 cm#, by how much must the centripetal force applied by the tracks change?

Question

1053 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-12T14:01:34

The centripetal force is #0.1N#

The centripetal force is

#F=(mv^2)/r#

The variation in centripetal force is

#DeltaF=(mv^2)/(Delta r)#

#=(8*(0.15)^2)/(2.25-0.45)#

#=(8*0.0225)/1.8#

#=0.1N#