A model train with a mass of #5 kg# is moving along a track at #14 (cm)/s#. If the curvature of the track changes from a radius of #84 cm# to #28 cm#, by how much must the centripetal force applied by the tracks change?

Question

982 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-06T12:59:39

The centripetal force changes by #=0.23N#

The centripetal force is

#F=(mv^2)/r#

mass, #m=5kg#

speed, #v=0.14ms^-1#

radius, #=r#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=5*0.14^2/0.84=0.12N#

#F_2=5*0.14^2/0.28=0.35N#

#DeltaF=0.35-0.12=0.23N#