A model train, with a mass of #4 kg#, is moving on a circular track with a radius of #6 m#. If the train's kinetic energy changes from #24 j# to #96 j#, by how much will the centripetal force applied by the tracks change by?

1 Answer
P dilip_k
Mar 27, 2016

Mass of the train m= 4kg
The radius of circular path (r)=6m
Initial velocity,#v_1#
final velocity,#v_2#
Initial KE,#=1/2mv_1^2#
final KE,#1/2mv_2^2#
Change in KE =#1/2mv_2^2-1/2mv_1^2=96-24=72J#
Dividing both sides of this equation by radius (r)of circular path and multiplying both sides by 2 we have
#mv_2^2/r-mv_1^2/r=2*72/r#
We see that left side of the equation is the change in centripetal force
So The change in centripetal force is #=2*72/r=2.72/6(N.m)/m=24N#

Related questions
See all questions in Circular Motion
Impact of this question
1324 views around the world
You can reuse this answer
Creative Commons License