A model train with a mass of #4 kg# is moving along a track at #6 (cm)/s#. If the curvature of the track changes from a radius of #32 cm# to #45 cm#, by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2018-04-06T05:55:16

The change in centripetal force is #=0.013N#

The centripetal force is

#vecF_C=(mv^2)/r*vecr#

The mass is of the train #m=4kg#

The velocity of the train is #v=0.06ms^-1#

The radii of the tracks are

#r_1=0.32m#

and

#r_2=0.45m#

The variation in the centripetal force is

#DeltaF=F_2-F_1#

The centripetal forces are

#||F_1||=4*0.06^2/0.32=0.045N#

#||F_2||=4*0.06^2/0.45=0.032N#

#DeltaF=F_1-F_2=0.045-0.0032=0.013N#