A model train, with a mass of 3 kg, is moving on a circular track with a radius of 2 m. If the train's rate of revolution changes from 5/4 Hz to 1/8 Hz, by how much will the centripetal force applied by the tracks change by?

1 Answer
Feb 11, 2017

The change in centripetal force is =299.8N

Explanation:

The centripetal force is

F=mr omega^2

The variation in centripetal force is

Delta F=mr (Delta omega)^2

Delta F =3*2*(2pi(5/4-1/8))^2

=24 pi^2 (81/64)

=299.8N