A model train with a mass of #3 kg# is moving along a track at #8 (cm)/s#. If the curvature of the track changes from a radius of #21 cm# to #18 cm#, by how much must the centripetal force applied by the tracks change?

Question

888 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-14T12:20:37

The change in centripetal force is #=0.016N#

The centripetal force is

#F=(mv^2)/r#

mass, #m=3kg#

speed, #v=0.08ms^-1#

radius, #=(r) m#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=mv^2/r_1=3*0.08^2/0.21=0.091N#

#F_2=mv^2/r_2=3*0.08^2/0.18=0.107N#

#DeltaF=0.107-0.091=0.016N#