A model train with a mass of #3 kg# is moving along a track at #8 (cm)/s#. If the curvature of the track changes from a radius of #4 cm# to #18 cm#, by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-02-11T11:03:46

The change in centripetal force is #=0.12N#

The centripetal force is

#F=(mv^2)/r#

The variation in centripetal force is

#DeltaF=(mv^2)/(Delta r)#

#=(3*(0.08)^2)/(0.18-0.04)#

#=(3*0.08*0.08)/0.16#

#=0.12N#