A model train with a mass of #2 kg# is moving along a track at #3 (cm)/s#. If the curvature of the track changes from a radius of #4 cm# to #12 cm#, by how much must the centripetal force applied by the tracks change?

Question

947 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-08-12T07:05:39

The change in centripetal force is #=0.03N#

The centripetal force is

#F=(mv^2)/r#

The mass, #m=(2)kg#

The speed, #v=(0.03)ms^-1#

The radius, #=(r) m#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=mv^2/r_1=2*0.03^2/0.04=0.045N#

#F_2=mv^2/r_2=2*0.03^2/0.12=0.015N#

#DeltaF=0.045-0.015=0.03N#