A model train, with a mass of 1 kg, is moving on a circular track with a radius of 5 m. If the train's rate of revolution changes from 1/9 Hz to 1/5 Hz, by how much will the centripetal force applied by the tracks change by?

1 Answer
Oct 2, 2017

The change in centripetal force is =1.56N

Explanation:

The centripetal force is

F=mr omega^2

The mass is m=1kg

The radius r=5m

The change in angular velocity is

Delta omega=(1/5-1/9)*2pi=(8/45pi)rads^-1

The variation in centripetal force is

DeltaF=mr(Delta omega)^2

=1*5*(8/45pi)^2

=1.56N