A mixture of #"N"_2#, #"O"_2#. and #"CO"_2# has a total pressure of #"740 torr"# In this mixture, the partial pressure of #"N"_2# is #"120 torr"# and the partial pressure of #"O"_2# is #"400 torr"#. What is the partial pressure of #"CO"_2# ?

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Answer 1 · 2018-02-24T09:40:48

#"220 torr"#

From Dalton's Law of Partial Pressures, the total pressure of a mixture of gases is the sum of the partial pressures of each gas.

Therefore, the partial pressure of #"CO"_2# is

#"740 torr " - " 120 torr " - " 400 torr = 220 torr"#

Answer 2 · 2018-02-24T09:42:47

#220"torr"#

According to Dalton's Law of Partial Pressures,

#P_"total"=SigmaP_i#, or #P_"total"=P_1+P_2+....P_n#

Here, we can write the above as:

#P_"total"=P_(N_2)+P_(CO_2)+P_(O_2)#

Here,

#P_"total"=740"torr"#

#P_(N_2)=120"torr"#

#P_(O_2)=400"torr"#

Inputting, we get:

#740=120+400+P_(CO_2)#

#740=520+P_(CO_2)#

#P_(CO_2)=220"torr"#