A mass of 45.0 grams of aluminum will react with how many grams of zinc chloride?

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Answer 1 · 2016-04-12T16:26:02

#328.6 g/(mol)#

In order to solve this problem we need to begin with a balanced chemical equation.

Zinc Chloride #(ZnCl_2 - Zn^+2 and Cl^-1)#
Reacts with Aluminum in solution to form
Aluminum Chloride #(AlCl_3 - Al^+3 and Cl^-1)#

#2Al + 3ZnCl_2 -> 2AlCl_3 + 3Zn#

Now we must use stoichiometry to convert grams of Al to grams of ZnCl_2

molar mass of aluminum is #27.99 g/(mol)#

molar mass of zinc chloride is #136.29 g/(mol)#
Zn #65.39#
Cl #2(35.45) = 70.90#
#65.39 +70.90 = 136.329#

the mole ratio of #ZnCl_2# to #Al# is #3:2#

grams #-># moles #-># moles #-># grams

#45 g Al# x #(1 cancel(mol Al))/(27.99 cancel(g Al))# x #cancel(3 (mol ZnCl_2))/(2 cancel(mol Al))# x #(136.29 g ZnCl_2)/(1 cancel(mol ZnCl_2))# =

#(45(3)(136.29))/((27.99)(2))# = #328.6 g/(mol)#