A line segment has endpoints at (9 ,2 ) and (7 , 4). The line segment is dilated by a factor of 3 around (1 , 5). What are the new endpoints and length of the line segment?

1 Answer
May 13, 2018

(9,2) to (25, -4)

(7,4) to (19,2)

New length 6 sqrt{2}

Explanation:

There is indeed a Bolivia, United States, in North Carolina, not too far from Myrtle Beach.

I did the general case of this question [here].(https://socratic.org/questions/a-line-segment-has-endpoints-at-2-4-and-5-3-the-line-segment-is-dilated-by-a-fac-1)

I got for endpoints (a,b),(c,d), and factor r around dilation point (p,q):

(a,b) to ( (1-r)p + ra, (1-r)q+ rb) , similarly for (c,d),

new length l = r \sqrt{ (a-c)^2 + (b-d)^2 }

These are old problems that probably no one ever looks at that I think are just here to give the noobs something to do. I'm an old timer at 26 days; I only answered because of Bolivia, United States.

I will now mindlessly substitute.

a=9,b=2,c=7,d=4,p=1,q=5,r=3

(9,2) to ( (1-3)1 + 3(9), (1-3)5+ 3(2))= (25, -4)

(7,4) to ( (1-3)1 + 3(7), (1-3)5+ 3(4)) = (19,2)

new length l = 3 \sqrt{ (9-7)^2 + (2-4)^2 } = 3 sqrt{8} =6 sqrt{2}