A line passes through #(4 ,3 )# and #(7 ,1 )#. A second line passes through #(1 ,8 )#. What is one other point that the second line may pass through if it is parallel to the first line?

1 Answer
MathFact-orials.blogspot.com
May 29, 2016

Find the slope of the first line, then apply it to the point of the second line to find #(1+3,8-2)=(4,6)#

Explanation:

We can solve this by finding the slope of the first line, then applying that slope to the point of the second line.

The first line passes through points #(4,3) and (7,1)#. Let's determine the slope.

The equation of slope is #m=(y_2-y_1)/(x_2-x_1)#. Let's plug in our points into this equation:

#m=(1-3)/(7-4)=-2/3#

We can now apply this slope to point #(1,8)#. I'll move 3 to the right on the x axis and 2 down on the y:

#(1+3,8-2)=(4,6)#

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