A gas with a volume of 3.00 x 10^2 mL at 150.0 degrees C is heated until its volume is 6.00 X 10^2 mL. What is the new temperature of the gas if the pressure remains constant during the heating process?

1 Answer
Jun 4, 2017

We use old Charles' Law, VpropT; units of "absolute temperature" must be used, 0 ""^@C=273.15*K.

Explanation:

We use old Charles' Law, which states that at constant pressure, and a given quantity of gas, volume varies with temperature.........i.e. VpropT.

And thus V=kT. And if we solve for k, we gets the relationship....

V_1/T_1=V_2/T_2 for a given quantity of gas.......

T_2=(V_2xxT_1)/V_1, "absolute temperature" is used......

=(600*mLxx423.15*K)/(300*mL)=846.3*K. Can you convert this temperature to ""^@C?