A force of magnitude F_1F1 accelerates a body of mass mm from rest to speed vv. Another force F_2F2 accelerates a body of mass 2m2m from rest to a speed 2m2m. What is the ratio of the work done by F_2F2 to that of F_1F1?

1 Answer
Nov 24, 2016

W_2 / W_1 = 8W2W1=8

Explanation:

We assume that the statement contains an error: where it says that the force F_2F2 accelerates a body of mass 2 m2m from rest to a speed 2m2m, we understand that it should say that F_2F2 accelerates said body to a speed 2 v2v. In another case, the statement would not make much sense.

That said, we will solve the problem.

The work done by force on the body will be equal to the variation of the kinetic energy that it experiences:

W = Delta K = 1/2 m (v^2 - cancel {v_0^2}) = 1/2 m v^2

As both bodies start from rest, their initial velocities are two equal to zero.

The work done by the first force will be:

W_1 = 1/2 m v^2

and the one done by the second is:

W_2 = 1/2 (2 m) cdot (2 v)^2 = 4 m v^2

Then, the ratio between W_2 and W_1 is:

W_2 / W_1 = {4 m v^2}/{1/2 m v^2} = 8