lim h -> 0 ? Calculus Limits Introduction to Limits 1 Answer Cesareo R. Jan 15, 2017 9 Explanation: f(x)=abs(-9x-7)=abs(9x+7) (f(6+h)-f(6))/h=(abs(9(6+h)+7)-abs(9xx6+7))/h= (abs(61+9h)-61)/h = 9((abs(61/9+h)-61/9)/h) now a) if h > 0->abs(61/9+h)=61/9+h so 9((abs(61/9+h)-61/9)/h)=9(61/9+h-61/9)/h=9 b) if h < 0->abs(61/9-h)=61/9-h so 9((abs(61/9+h)-61/9)/h)=9(61/9-h-61/9)/(-h)=9 No limit is required. Answer link Related questions How doI find limits in calculus? How do limits work in calculus? What exactly is a limit in calculus? What is the purpose of a limit in calculus? What is rational function and how do you find domain, vertical and horizontal asymptotes. Also... lim x-->-1- f(x) = ? How do you use the Squeeze Theorem to show that limsinx/x as x approaches infinity? How do you use the Squeeze Theorem to show that sqrt (x) * e^(sin(pi/x))=0 as x approaches zero? How do you use the Squeeze Theorem to find lim xcos(1/x) as x approaches zero? How do you use the Squeeze Theorem to find lim x^2 (Sin 1/x)^2 as x approaches zero? See all questions in Introduction to Limits Impact of this question 2281 views around the world You can reuse this answer Creative Commons License