A flower pot with a mass of 6.8kg is hanging by 4 wires that make an angle of 53° from the horizontal. What is the tension on each wire?

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Answer 1 · 2015-11-02T22:37:43

$"T"=20.8"N"$

The weight of the flower pot is supported by the tension in the 4 wires.

The vertical component of the tension will be $Tcos(90-53)=Tsin(53)$ .

Since there are 4 wires, these will all support the weight $"W"$ .

So we can write:

$W =4Tsin(53)$

The weight $W$ is given by:

$W=mg$

$:.T=(W)/(4sin(53))$

$T=(6.8xx9.8)/(4xx0.8)$

$T=20.8"N"$