A farmer wants to fence an area of 6 million square feet in a rectangular field and then divide it in half with a fence parallel to one of the sides of the rectangle. How can he do this so as to minimize the cost of the fence?

1 Answer
Jun 17, 2018

If the rectangular field has notional sides x and y, then it has area:

  • A(bbx) = xy qquad [= 6*10^6 " sq ft"]

The length of fencing required, if x is the letter that was arbitrarily assigned to the side to which the dividing fence runs parallel, is:

  • L (bbx) = 3x + 2y

It matters not that the farmer wishes to divide the area into 2 exact smaller areas.

Assuming the cost of the fencing is proportional to the length of fencing required, then:

  • C(bbx ) = alpha L(bbx)

To optimise cost, using the Lagrange Multiplier lambda, with the area constraint :

  • bbnabla C(bbx) = lambda bbnabla A

  • bbnabla L(bbx) = mu bbnabla A

implies mu = 3/y = 2/x implies x = 2/3 y

  • implies xy = {(2/3 y^2),( 6*10^6 " sq ft"):}

:. qquad qquad {(y = 3*10^3 " ft"),(x = 2* 10^3 " ft"):}

So the farmer minimises the cost by fencing-off in the ratio 2:3, either-way