A distribution has a standard deviation of $σ = 8$ $sigma=8$ . How do you find the z-score below the mean by 8 points?

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Answer 1 · 2018-06-28T15:08:28

-1

Formula for Z is $Z = \frac{(x - ¯ x)}{(standard deviation)}$ $Z = ((x - bar x))/("(standard deviation)")$

In this case, $x - ¯ x$ $x - bar x$ is given as -8 (below the mean), and the standard deviation is 8, therefore

$Z = \frac{- 8}{8}$ $Z = (-8)/(8)$ = -1.

A distribution has a standard deviation of σ=8sigma=8. How do you find the z-score below the mean by 8 points?