A cyclist increases his kinetic energy from 11 00 J to 5 200 J in 12 s. How can I calculate his power output during this time?

1 Answer
Alexander L.
Apr 9, 2015

Power is the rate of change of output energy.

#P=dE/dt# or #P=(DeltaE)/(Deltat)#

Having said that, the change in energy

#DeltaE= E_f - E_i=5200J-1100J#

and your time interval #Deltat=12s#.

Voila!

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