A converging lens is used to project a 250 mm image of a square slide onto a screen 1000 mm away. the focal length of the lens is 200 mm. by means of scale drawing, determine---(a) the distance of the slide from the lens----(b) the size of the slide???

please explain it to me...

1 Answer
Jun 30, 2016

(a)Distance of the slide from lens = 250 mm

(b) The size of the slide = 62.5 mm

Explanation:

self drawn

Given

  • s_i->"Size of the image"=250mm
  • v->"Image distance"=+1000mm
  • f-> "Focal length of convex lens"=+200mm

We are to find out

  • u->"object distance"=?

  • s_o->"Size of the object"=?

Calculation

Lens formula

color(blue)(1/v-1/u=1/f)

Plugging the values

=>1/1000-1/u=1/200

=>1/u=1/1000-1/200=(1-5)/1000=-1/250

color(red)(=>u=-250mm)

color(green)("-ve sign means real object")

Now magnification (m)

m = s_i/s_o=v/u

=>250/s_o=1000/250=4

color(red)(=>s_o=250/4=62.5mm)

The distance of the slide from lens (u)=250mm.

The size of the slide =62.5mm